Question: We need to find all points (x, y) for which (2x - 8)i + (2y - 10)j is parallel to i + j. So we

We need to find all points (x, y) for which (2x

We need to find all points (x, y) for which (2x - 8)i + (2y - 10)j is parallel to i + j. So we must solve (2x - 8)i + (2y - 10)j = k[i + j]. This means that k = 2x - 8 and k = 2y - 10. Equating these gives us

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