We need to write down the solving in detail.

Determine if the specied linear transformation is {a} onetoone and {b} onto. Just'rfv your answer. T[:x1,xz,x3,x4) =[x2 +x3,x3 +K4,U,){2 \"(3} a. Is the linear transformation onetoone'? C} A. T is net onetoone because the standard matrix A has a free variable. C} E. T is not onetoone because the columns of the standard matrixA are linearly independent. C} C. T is onetoone because the column vectors are not scalar multiples of each other. C} D. T is onetoone because T[x} = I] has only the trivial solution. b. Is the linear transformation onto? 0 A. T is not onto because the third rov-r ot the standard matrix A is all zeros. {j E. T is not onto because the columns of the standard matrix A span 3"\". Cl C. T is onto because the columns of the standard matrix A span R4. {2} [)_ T is onto because the standard matrix A does not have a pivot position for every:r row