Question: We want to implement another sorting algorithm called insertion sort. For doing that, we iterate over all elements in the input array. As we examine

We want to implement another sorting algorithm called insertion sort.
For doing that, we iterate over all elements
in the input array. As we examine each element, we perform a series of swaps to
move it to the place it belongs in the sorted left side of the array.
As example, consider the array [2; 4; 5; 3](in math notation):
We first consider the element 2 at index 0. Since there is nothing to its left,
we dont need to do anything to sort the array up to this index.
Next we consider 4 at index 1. The element to its left, 2, is smaller. If
we understand [2] as a sorted array, then 4 needs to remain to its right.
Therefore no swap is necessary.
Next we consider 5 at index 2. The array [2; 4] to its left is sorted. Again
5 is larger than 4, so we dont need to perform any swap to make the array
[2; 4; 5] sorted.
Finally, we consider 3 at index 3. This element is smaller than 5 to its
left. Therefore, we will need to perform at least one swap to place 3 in its
sorted position. Thus, we swap 3 with 5, obtaining the array [2; 4; 3; 5],
where 3 is larger than the element to its left, 2. Therefore we swap 3 with 4,
obtaining [2; 3; 4; 5]. Now, 3 is larger than 2, and therefore no further swaps
are needed.
Since we have gone through all the elements of the input array, the array we
obtained, [2; 3; 4; 5] is the final sorted array.
Draw pictures to figure out what portion of
the array is sorted at each point.
Express your findings as loop invariants using
functions in the array_util library.
Implement the function in the docker in a new file insort.c0 by using the same interface of selsort.c0(lab3)
Test and measure the time of the new sorting algorithm by using the main in sort-time.c0(lab3). What is the run time of this sorting algorithm?

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