We wish to compute 12 +1 dr . 13 + 412 - 161 - 64 (i) We begin by factoring the denominator of the rational function. We get 1 + 4x - 161 - 64 = (x - a) (x -b)2 for a b . What are a and b ? FORMATTING: Make sure b corresponds to the factor of the denominator that repeats twice. 1 = Number b= Number (ii) Next, we express the fraction in the form 12 +1 A B -- 13 + 412 - 161 - 64 b (I - b)2 Give the exact values of A , B and C FORMATTING: Make sure A, B, and C correspond to the appropriate denominators, as given in the above setup. A = B = C = (iii) Finally, we use this partial fraction decomposition to compute the integral. Give its approximate value with 3 decimal places. 12 + 1 Number 3 13+ 4x2 - 161 - 64