Question: We wish to compute 3 3x + 5 dx . 23 + 3x (i) We begin by noting that 23 + 3x = x(24+ 3)


We wish to compute 3 3x + 5 dx . 23 + 3x (i) We begin by noting that 23 + 3x = x(24+ 3) where a + 3 is a polynomial of degree two with no real roots. We can thus write 3x + 5 A Bx + C + 23 + 3x 20 2 + 3 Give the exact values of A, B and C. A = Number B = Number and C= Number (ii) Finally, we use this partial fraction decomposition to compute the integral. Give its approximate value to 3 decimal places. .3 3x +5 da ~ Number 23 + 3x
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