what did i do wrong, and what would be the correct answer

Based on the thermodynamic properties provided for water, determine the amount of energy released for 155.0g of water to go from 41.0C to 19.5C (1) Determine the amonl of energy reloased for 150.09 of H20 to go from 410c to 19.5c (1) a=mcT (2) a=nH&u (3) Q=MCT (1) Q=MCT=( Mass) (specific temp) (Change in temp) MassofH20=150Og(4)specifictemp=75.3J/molC(3)change=41.0c0.0c(150.0g)(75.3.1molc)(41.0C)=462095J (2) Q=nHfux=( Moles )( given) 150.0gH2O18.01528g1mol=8.326265259(8.3262)(6.01kJ/mol)k=1000x=50.04085421kJ (3) Q=H(T= (mass) (specifie temp) (change) Mass of H20=150Og specific temp. 37.1 ' 1mol. C (3) change=195C=0.0C(150.0g)(37.1)lm61&)(19.5)=1085175s (463,095k)4(50,04085421)+(108,5175) =521.5716458 =522kJ