What did I do wrong in these two questions?

Week 11 quiz: Attempt review - Google Chrome - 0 X moodle.telt.unsw.edu.au/mod/quiz/review.php?attempt=12541939&cmid=5058006 Question 1 Consider the ODE Partially correct dy dt 2.4 - 2 . t t Mark 7 out of 10 Quiz navigation 1. The integrating factor for solving this ODE via the integrating factor method takes the form ed P(t) dt. What is the function p(t) for this P Flag question ODE? -2/t Finish review Your last answer was interpreted as follows: =2 1 The variables found in your answer were: [t] 2. What is S p(t) dt? (You can restrict yourself to t > 0.) In(1/t12) Your last answer was interpreted as follows: In () The variables found in your answer were: [t] 3. Using the integrating factor method, the expression for the solution to this ODE for a domain that includes t = 3 can be written as (do not bring signs outside of the integral): y ( t ) = 1 2 -2/t dt Your last answer was interpreted as follows: 2 The variables found in your answer were: [t] Your last answer was interpreted as follows: =2 The variables found in your answer were: [t] 4. The integral in part 4 evaluates to: In(1/t^2)+C Your last answer was interpreted as follows: In ( ) + c The variables found in your answer were: [C, t] 5. The expression for the general solution is thus: y(t) = t^2*[In(1/t^2)+C] Your last answer was interpreted as follows: 12 . In ( ) + c] The variables found in your answer were: [C, t] 15.C Cloudy W ENG ~ 4 0 4:26 PM 10/8/2022Week 11 quiz: Attempt review - Google Chrome - 0 X moodle.telt.unsw.edu.au/mod/quiz/review.php?attempt=12541939&cmid=5058006 Question 2 Consider the ODE Partially correct dy = 4+ 1 Quiz navigation Mark 8 out of 10 1. What is the integrating factor el p(t) dt? (You can restrict yourself to t > 0.) |1/t p Flag question Finish review Your last answer was interpreted as follows: - 1 The variables found in your answer were: [t] 2. What is the inverse of the integrating factor e-Jp(t) dt? (You can restrict yourself to t > 0.) t Your last answer was interpreted as follows: t The variables found in your answer were: [t] 3. What is the expression for the general solution (call the constant of integration c and do not redefine it): y(t) = -1/(2*t ) + C* Your last answer was interpreted as follows: ? + C . t The variables found in your answer were: [C, t] 4. What is the particular solution if y(1) = 1? y(t) = -1/(2*t) + 3/2*t Your last answer was interpreted as follows: 27 + 2 . t The variables found in your answer were: [t] Finish review Academic Integrity UNSW staff and students experiencing difficulties using Page last updated Monday 10 May 2021 Moodle? Contact External TELT Support for assistance. Privacy UNSW CRICOS Provider Code 00098G, ABN 57 195 873 Email: externalteltsupport@unsw.edu.au 179 | Sydney, NSW.2052, Australia Content & Social Media Disclaimer Internal: x53331 15 C ENG 1 0 4:26 PM Cloudy 10/8/2022