Question: What does the following code segment do ? int j = 0 ; do { cout j * 7 endl; j + + ; }

What does the following code segment do?
int j =0;
do{
cout j*7 endl;
j++;
}while(j =10);
Group of answer choices
Produces a syntax error.
Prints the multiples of 7 up to 63.
Prints the product of all the integers less than or equal to 10.
Prints the multiples of 7 up to 70.
What does the following code segment do? int j =0; do{

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