Question: What happens when we write this code snippet? int x = 1; int x = x + 1; x = x + 1; System.out.println(x); Question

What happens when we write this code snippet? int x = 1; int x = x + 1; x = x + 1; System.out.println(x);

Question 2 options:

It has a compile error because on the third line the type of x is not specified

It compiles, but has a runtime error when printing x because x has multiple values during the program

It compiles and runs correctly, and prints 3

It has a compile error because x cannot be declared twice

Retake question

What output would be produced by this code snippet? System.out.print(8); System.out.println("cats"); System.out.print(7);

Question 6 options:

8.0cats 7.0

8cats7

8cats 7

8 cats 7

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