What is $h^{\text{'}}(x)$ when $h(x)=ln(2x^{2}x3)?$

Select the correct answer below:

$\frac{1}{2x^{2}x3}$

$\frac{2x^{2}x3}{4x1}$

$ln(4x1)$

$\frac{4x1}{2x^{2}x3}$

$\frac{4x1}{ln(2x^{2}x3)}$