Question: What is L 1 ( 1 s 2 + 4 s + 1 3 ) displaystyle mathcal { L } ^ { -

What is L1(1s2+4s+13)\displaystyle \mathcal{L}^{-1}\!\Bigl(\tfrac{1}{s^2+4s +13}\Bigr)L1(s2+4s+131)?
Choices:
A.13e3tsin(2t)\tfrac{1}{3}e^{-3t}\sin(2t)31e3tsin(2t)
B. e2tsin(3t)e^{-2t}\sin(3t)e2tsin(3t)
C.13e2tsin(3t)\tfrac{1}{3}e^{2t}\sin(3t)31e2tsin(3t)
D.13e2tsin(3t)\tfrac{1}{3}e^{-2t}\sin(3t)31e2tsin(3t)

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