What is $t^{\text{'}}(x)$ when $t(x)=7e^{x^{-3}}?$

Select the correct answer below:

$t^{\text{'}}(x)=7e^{x^{\text{'}}}$

$t^{\text{'}}(x)=-56x^{-8}{e}^{x^2}$

$t^{\text{'}}(x)=-56x^{-9}{e}^{x^{-}}$

$t^{\text{'}}(x)=-56e^{x^{-}}$