What is the average concentration of NaOH solution provided theaverage mL of NaOH added in 3 titrations?
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What is the average concentration of NaOH solution provided theaverage mL of NaOH added in 3 titrations? I have provided some ofmy previous answers for reference. Thanks.
2. Amount of benzoic acid to be neutralized by 20 mL NaOH solution,in both moles and grams:
NaOH [M]= 0.020 L*0.494 M= 0.00988 M Benzoic acid [M] = 0.00988 moles Benzoic acid (g)= 0.00988 mol*122.12 g/mol = 1.207 g
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3. Actual mL values of NaOH solution delivered in 3titrations:
Titration #1 | 20.07mL |
Titration #2 | 20.07mL |
Titration #3 | 20.07mL |
4. Calculated average concentration of the NaOH solution,using the average mL amount of NaOH added in the 3 finetitrations:
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