Question: What is the average concentration of NaOH solution provided theaverage mL of NaOH added in 3 titrations? I have provided some ofmy previous answers for

What is the average concentration of NaOH solution provided theaverage mL of NaOH added in 3 titrations? I have provided some ofmy previous answers for reference. Thanks.

2. Amount of benzoic acid to be neutralized by 20 mL NaOH solution,in both moles and grams:

NaOH [M]= 0.020 L*0.494 M= 0.00988 M

Benzoic acid [M] = 0.00988 moles

Benzoic acid (g)= 0.00988 mol*122.12 g/mol = 1.207 g

3. Actual mL values of NaOH solution delivered in 3titrations:

Titration #1	20.07mL
Titration #2	20.07mL
Titration #3	20.07mL

4. Calculated average concentration of the NaOH solution,using the average mL amount of NaOH added in the 3 finetitrations:

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