Yield strength of connecting rod number 2 shown in the figure S_y = 100 MPa of low-carbon steel manufactured. The modulus of elasticity is E=200 GPa.

The tensile strength of the material is S_ut = 160 Mpa. A general variable load F between 6 and 10 kN acts on the system from point C as shown in the figure. Based on this ;

a) Draw the necessary free-body diagram to find the force on the connecting rod. Find the mean and amplitude stresses on the connecting rod depending on the diameter d of the rod.

b) The drawbar is forged and 99% reliability is required. Find the finite life strength (S_f) if a life of 100 000 cycles is desired in the design.

c) If the design factor of safety n_f = 2 is desired, what should the diameter d of the connecting rod be? Calculate.

Note : For finite life calculations, take the variable f as 1.

 

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What is the balanced chemical equation for the reaction used to calculate AHof of CaCO3(s)? If fractional coefficients are required, enter them as a fraction (i.e. 1/3). Indicate the physical states using the abbreviation (s), (1), or (g) for solid, liquid, or gas, respectively without indicating allotropes. Use (aq) for aqueous solution. Express your answer as a chemical equation. The standard enthalpy of formation (AHof) is the enthalpy change that occurs when exactly 1 mol of a compound is formed from its constituent What is the balanced chemical equation for the reaction used to calculate AHof of CaCO3(s)? If fractional coefficients are required, enter them as a fraction (i.e. 1/3). Indicate the physical states using the abbreviation (s), (1), or (g) for solid, liquid, or gas, respectively without indicating allotropes. Use (aq) for aqueous solution. Express your answer as a chemical equation. The standard enthalpy of formation (AHof) is the enthalpy change that occurs when exactly 1 mol of a compound is formed from its constituent

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a Freebody diagram freebody diagram of a connecting rod The forces acting on the connecting rod are F The variable load acting at point C RA The react... View the full answer