What is the code to solve this problem ?

yKy(x)(1+(y(x))2)(3/2) We have that y(0)=y(L)=0 and y(L/2)=a, where y(x) is the height above the water and a) If, for the sake of simplicity, you start at the midpoint of the bridge and solve the differential equation up to x=L with K=2104 and a=26 meters, what height do you end up at when x=L ? b) Determine the K value needed for the bridge to actually end at y(L)=0. c) d) The arc length in part question c will be close to 106. If one is allowed to adjust the sail-free height of the bridge (i.e. a) so that the symmetrical bridge both ends in y(L):0 and has the arc length 110 , what value of constant K= is needed and how high will the bridge be then