Question: What is the efficiency of an algorithm with a complexity of N log N ? a . The efficiency of N log N is equal

What is the efficiency of an algorithm with a complexity of N log N?
a.
The efficiency of N log N is equal to N^2, as they both have the same growth rate.
b.
The efficiency of N log N is worse than N^2, as it has a higher growth rate.
c.
The efficiency of N log N is better than N^2, as it has a lower growth rate.
d.
The efficiency of N log N and N^2 cannot be compared as they represent different types of algorithms.

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