Question: What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fair-shared (i.e., divides its

What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fair-shared (i.e., divides its transmission rate equally among the four pairs)?
| 20 Mbps | ||
| 25 Mbps | ||
| 40 Mbps | ||
| 100 Mbps |
Which link is the bottleneck link?
| The links from the servers to the shared link | ||
| The middle link | ||
| The links from the shared middle link to the clients | ||
| None of the above |
Assuming that the senders are sending at the maximum rate possible, what are the link utilizations for the sender links (Rs), client links (Rc), and the middle link (R)?
| The utilization of server links is 25% (25Mbps/100Mbps). The utilization of receiver links is 62.5% (25Mbps/40Mbps) . The utilization of the middle link is 100% (25Mbps/25Mbps) .
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| The utilization of server links is 100% (100Mbps/100Mbps). The utilization of receiver links is 100% (40Mbps/40Mbps) . The utilization of the middle link is 40% (40Mbps/100Mbps) .
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| The utilization of server links is 25% (25Mbps/100Mbps). The utilization of receiver links is 62.5% (25Mbps/40Mbps) . The utilization of the middle link is 40% (40Mbps/100Mbps) .
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| None of the above |
Consider the scenario shown below, with four different servers connected to four different clients over four three-hop paths. The four pairs share a common middle hop with a transmission capacity of R = 100 Mbps. The four links from the servers to the shared link have a transmission capacity of RS = 100 Mbps. Each of the four links from the shared middle link to a client has a transmission capacity of RC = 40 Mbps per second. R = 100 Mbps Rs 100 Mbps Rs= 100 Mbps R = 100 Mbps R = 100 Mbps Rc= 40 Mbps Rc= 40 Mbps Rc= 40 Mbps Rr= 40 Mbps What is the maximum achievable end-end throughput (in Mbps) for each of four client-to-server pairs, assuming that the middle link is fair-shared (i.e., divides its transmission rate equally among the four pairs)
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