Question: What is the output of C code below? #include int main int *ptr; int X ptr 0 printf(X-%d , x); printf( *ptr-%d , *ptr); ptr5

What is the output of C code below? #include int main

What is the output of C code below? #include int main int *ptr; int X ptr 0 printf("X-%d ", x); printf(" *ptr-%d ", *ptr); ptr5 printf("X-%d ", x); printf(" *ptr-%d ", *ptr); ("ptr)++; printf("X-%d ", x); printf(" *ptr-%d ", *ptr); return 0

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