what is the output of following code? void main() { int x, y=1, tot=0; (x=1;x

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what is the output of following code? void main() { int x,y=1, tot=0; (x=1;x <5;x+=4) for { }| } if(x==4) continue; tot+=x*y++; cout <

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Computer Systems A Programmers Perspective

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Posted Date: Jan 21, 2024 05:11 PM

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what is the output of following code? void main() { int x, y=1, tot=0; (x=1;x

Question:

void main() { int x, y=1, tot=0; (x=1;x<5;x+=4) for { }| } if(x==4) continue; tot+=x*y++; cout<<tot<<endl; if(y==4) break; void main() { int x, y=1, tot=0; (x=1;x<5;x+=4) for { }| } if(x==4) continue; tot+=x*y++; cout<<tot<<endl; if(y==4) break;

Expert Answer:

The code provided seems to be in C and contains a main function with a loop that calculates some val... View the full answer

Computer Systems A Programmers Perspective

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void main() { int x, y=1, tot=0; (x=1;x<5;x+=4) for { }| } if(x==4) continue; tot+=xy++; cout<<tot<<endl; if(y==4) break; void main() { int x, y=1, tot=0; (x=1;x<5;x+=4) for { }| } if(x==4) continue; tot+=xy++; cout<<tot<<endl; if(y==4) break;