What is the output of the following code? int num]{1, -2, 3, 2, -1}; int pNum1...

   

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What is the output of the following code? int num]{1, -2, 3, 2, -1}; int pNum1 num+ 1; int pNum2 num + 2; int pNum3 &pNum1; int pNum4 -&pNum2; pNum2 +pNum1; pNum1+ (pNum4 + 2); int sum *pNum1+ "pNum2+ *pNum3+ **pNum4; printf("%d", sum); What is the output of the following code? int num] {1, -2, 3, 2, -1}; int pNum1 num+ 1; int pNum2- num + 2; int pNum3= &pNum1; int pNum4 -&pNum2; pNum2 + pNum1; pNum1+ (pNum4 + 2); int sum *pNum1+ "pNum2+ *pNum3 + pNum4; printf("%d", sum); W What is the output of the following code? int num]{1, -2, 3, 2, -1}; int pNum1 num+ 1; int pNum2 num + 2; int pNum3 &pNum1; int pNum4 -&pNum2; pNum2 +pNum1; pNum1+ (pNum4 + 2); int sum *pNum1+ "pNum2+ *pNum3+ **pNum4; printf("%d", sum); What is the output of the following code? int num] {1, -2, 3, 2, -1}; int pNum1 num+ 1; int pNum2- num + 2; int pNum3= &pNum1; int pNum4 -&pNum2; pNum2 + pNum1; pNum1+ (pNum4 + 2); int sum *pNum1+ "pNum2+ *pNum3 + pNum4; printf("%d", sum); W

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