Question: What is the output of the following code? The program has an error because x is private and cannot be accessed outside of the class.
What is the output of the following code? The program has an error because x is private and cannot be accessed outside of the class. The program runs fine and prints 1. The program runs fine and prints 45. The program has an error because y is private and cannot be accessed outside of the class. The program has an error because you cannot name a variable using __.y
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
