Question: What is the output of the given code ? int main( int argc, char** argv) { int *j = (int*)malloc(4 * sizeof(int)); //assume that malloc
What is the output of the given code ?
int main( int argc, char** argv) { int *j = (int*)malloc(4 * sizeof(int)); //assume that malloc will not return NULL *p = 15; free(p); printf("%d", *p); return EXIT_SUCCESS; }
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