what is the output of this code segment $"$# "New" means new compared to previous level

def scramble$\_$nums$($remain$\_$nums, scram$\_$nums$)$:

if len$($remain$\_$nums$)==0$:

print$($scram$\_$nums$[0],$ scram$\_$nums$[1],$ scram$\_$nums$[2],$ sep$=\text{'}\text{'})$

else:

for i in reversed$($range$($len$($remain$\_$nums$)))$: # New: This line changed

tmp$\_$remain$\_$nums $=$ remain$\_$nums$[$:$]$ # Make a copy.

tmp$\_$removed$\_$num $=$ tmp$\_$remain$\_$nums$[$i$]$

tmp$\_$remain$\_$nums.pop$($i$)$ # Remove element at i

scram$\_$nums.append$($tmp$\_$removed$\_$num$)$

scramble$\_$nums$($tmp$\_$remain$\_$nums, scram$\_$nums$)$

scram$\_$nums.pop$()$ # Remove last element

nums$\_$to$\_$scramble $=[]$

result$\_$nums $=[]$

nums$\_$to$\_$scramble.append$(9)$

nums$\_$to$\_$scramble.append$(1)$

nums$\_$to$\_$scramble.append$(4)$

scramble$\_$nums$($nums$\_$to$\_$scramble, result$\_$nums$)"$