Question: what is the runtime complexity The following code prints all strings of length k where the characters are in sorted order. It does this by

what is the runtime complexity The following code prints all strings of length k where the characters are in sorted order. It does this by generating all strings of length k and then checking if each is sorted. What is its runtime? int numchars =26; void printsortedstrings(int remaining){ printsortedstrings (remaining,""); } void printsortedstrings(int remaining, String prefix){ if (remaining ==0){ if (islnrder(prefix)){ system.out.println(prefix); }} else { for (int i =0; i < numchars; i++){ char c = ithLetter(i); printsortedstrings(remaining -1, prefix + c); }}} boolean islnorder(string s){ for (int i =1; i < s.length(); i++){ int prev ithLetter(s.charAt(i -1)); int curr = ithLetter(s.charAt(i)); if (prev > curr){ return false; }} return true; } char ithLetter(int i){ return (char)(((int)'a')+ i); }

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