Question: What is wrong with the following code, if anything? .equ Write_Int, 0x6B .equ Exit, 0x11 .text .global _start _start: @@ print out 25 mov

What is wrong with the following code, if anything? .equ Write_Int, 0x6B .equ Exit, 0x11 .text .global _start  

What is wrong with the following code, if anything? .equ Write_Int, 0x6B .equ Exit, 0x11 .text .global _start _start: @@ print out 25 mov r0, #25 mov r1, #1 swi Write Int swi Exit .end 2.) (3 pts) What value will be in register r0 at the end of the following code? mov r0, #0 mov r1, #5 cmp r1, #10 submi r0, rl, #2

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Answer There are a couple of issues with the provided assembly code swi is not a valid ARM in... View full answer

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