What is wrong with the following switch statement? int ans; cout $\text{'}$Type y for yes on $n$ for noln": cin $$ ans; switch $($ans$)$

I

case $y^2$ :

case $Y$ : cout $$ "You said yesin";

break;

case $\text{'}n$ :

case $\text{'}$N: cout $$ "You said noln";

break

default cout $"$invalid answer $n^n$;

$\}$

a$.$ ans is a int

b$.$ break is illegal syntax

c$.$ nothing

d$.$ there are no break statements on $2$ cases