What mass of Cu metal is required to react with 6.8 drops of 16M HNO3? Assume...

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What mass of Cu metal is required to react with 6.8 drops of 16M HNO3? Assume 20 drops = 1 mL. Cu (MM 63.54 g/mol), (16M = 16 mol/L) Cu(s) + 4HNO3(aq) à Cu(NO3)2(aq) + 2NO2(g) + 2H2O(1) Hint: x drops HNO, X. Cu mL X LX. mol X. mol X. drops mL L mol mol Give answer to 2 significant figures. Do not use scientific notation. After the number, include one space and then the unit, g. Do calculation all at once, round off at the end. What mass of Cu metal is required to react with 6.8 drops of 16M HNO3? Assume 20 drops = 1 mL. Cu (MM 63.54 g/mol), (16M = 16 mol/L) Cu(s) + 4HNO3(aq) à Cu(NO3)2(aq) + 2NO2(g) + 2H2O(1) Hint: x drops HNO, X. Cu mL X LX. mol X. mol X. drops mL L mol mol Give answer to 2 significant figures. Do not use scientific notation. After the number, include one space and then the unit, g. Do calculation all at once, round off at the end.

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Cu 4 HNO tal 2 NO 2 Hy a How Many moles 20 dvols 1 ml 61 v 034 m of 16... View the full answer