What will the following Python code output? def mystery_function (num): options_list = [0,2,4,6,8,10] new_list = []...

 

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What will the following Python code output? def mystery_function (num): options_list = [0,2,4,6,8,10] new_list = [] for i in options_list: if i % num > 3: new_list.append(i) return new list n = 8 print (mystery_function(n)) What will the following Python code output? def mystery_function (num): options_list = [0,2,4,6,8,10] new_list = [] for i in options_list: if i % num > 3: new_list.append(i) return new list n = 8 print (mystery_function(n))

Answer rating: 100% (QA)

To determine the output of the given Python code lets analyze the mysteryfunctionnum The function takes a single argument num which is used to iterate over the optionslist 0 2 4 6 8 10 For each element i in optionslist it checks if i num 3 If this condition is true it appends i to the newlist Finally the function returns newlist Given n 8 lets evaluate and determine which elements from optionslist satisfy the condition i 8 3 0 8 0 not greater than 3 2 8 2 not greater than 3 4 8 4 not greater than 3 6 8 6 not greater than 3 8 8 0 not greater than 3 10 8 2 not greater than 3 None of the elements in optionslist satisfy the condition so no elements are appended to newlist Therefore the function mysteryfunctionn ... View the full answer