Question: When a 2.10-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 3.02 cm. What is the force

When a 2.10-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 3.02 cm.

  1. What is the force constant of the spring?
  2. If the 2.10-kg object is removed, how far will the spring stretch if a 1.05-kg block is hung on it?
  3. How much work must an external agent do to stretch the same spring 6.50 cm from its unstretched position?

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