Question: When an electric current passes through two resistors with resistance r 1 and r 2 , connected in parallel, the combined resistance, R, is determined

When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance, R, is determined by the equation 1/R = 1/r1 + 1/r2 , (R > 0, r1 > 0, r2 > 0). Assume that r2 is constant, but r1 changes.

Find the expression for R through r1 and r2 and demonstrate that R is an increasing function of r1. You do not need to use derivative, give your analysis in words. Hint: a simple manipulation with the formula R = ... which you derive, will convert R to a form, from where the answer is clear. Make a sketch of R versus r1 (show r2 in the sketch). What is the practical value of R when the value of r1 is very large?

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