When an xx$-$ohm and a yy$-$ohm resistor are in parallel, the resistence RR they produce will be calculated from the formula

$1$R$=1$x$+1$y$\mathrm{.}1$R$=1$x$+1$y$.$

The values of xx and$$yy$$ are respectively $10$ and $20.$ Use

dR$=$R$$xdx$+$R$$ydydR$=$R$$xdx$+$R$$ydy

$$to estimate what percentage will$$RR change if xx$$ is increased by $10\%$ and yy$$ is decreased by $1\%?$

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Enter the numerical part of your answer to $2$ decimal places in the box below.

For example, if$$RR is increaded by $3\mathrm{.}17873\%,$ enter $3\mathrm{.}18$;

$$ if RR$$ is decreased by $2\mathrm{.}1235\%,$ enter $-2\mathrm{.}12.$

$$

Note: If you calculate the percentage change by

$[($new value of R$$R$$old value of RR$)/($old value of R$)]100\%$R$)]100\%$

your answer may be regarded as a wrong answer.