When reacting $50ml1MHCl$ with $50ml1$MNaOH solution, the temperature

of both solutions were $20C$ before mixing and it became $26C$ after adding $HCl$

solution to NaOH. If specific heat for $HCl$ and NaOH solution is $4\mathrm{.}18\frac{J}{g}C,$ density $=$

$1\frac{g}{m}l$ for both solutions and heat capacity of the cup is $10\frac{J}{}C.$

Calculate $H$ for the reaction as $K\frac{J}{?}$ mole $HCl$

a$)-2\mathrm{.}568KJ$

b$)-56\mathrm{.}68KJ$

c$)-51\mathrm{.}3KJ$

d$)-55\mathrm{.}3KJ$