When running experiments on lake on the planet Krypton $($which miraculously has the same free$-$fall acceleration as Earth, g$=9\mathrm{.}81$ m$/$s$2),$ you measure the pressure $12\mathrm{.}0$ m under the water's surface to be $2\mathrm{.}04$ x $105$ Pa $(1$ Pa$=1$ N$/$m$2).$ Assume the density of the water is $1000$ kg$/$m$3.$ At what depth below the waters surface would you measure a pressure of $1\mathrm{.}5$ x $105$ Pa $?$ HINT: Try solving first for the pressure P$0$ at the surface of the water; since this is an alien planet it probably won't be the same as on Earth! Also, remember in which direction the pressure should increase.