When solid $N{H}_{4}HS$ and $0\mathrm{.}400$ mole of gaseous $N{H}_3$ were placed into a $2\mathrm{.}0-L$ container

at $24C,$ the equilibrium $N{H}_{4}HS(s)N{H}_3(g)+H_{2}S(g)$ was reached. For this reaction,

$K_c=1\mathrm{.}6{10}^{-4}.$ What are the equilibrium concentrations of $N{H}_3$ and $H_{2}S?$