When switch SS in $($Figure $1)$ is open, the voltmeter VV of the battery reads $3\mathrm{.}10$ VV$.$ When the switch is closed, the voltmeter reading drops to $2\mathrm{.}88$ VV$,$ and the ammeter AA reads $1\mathrm{.}65$ AA$.$ Assume that the two meters are ideal, so they don't affect the circuit.

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Figure

$1$ of $1$

Part A

Find the emf.

Express your answer in volts.

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EE $=$

nothing

VV

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Part B

Find the internal resistance of the battery.

Express your answer in ohms.

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rr $=$

nothing

$$

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Part C

Find the circuit resistance RR$.$

Express your answer in ohms.