Question: When there are many possible values of interest, this task of adding up probabilities can be difficult. If we want to know the probability of

When there are many possible values of interest, this task of adding up probabilities can be difficult. If we want to know the probability of observing 8 or fewer heads from 10 coin flips, we need to add up the values from 0 to 8: P(0to8heads)+P(9to10heads)=P(0to10heads)=1 P(0to8heads)=1P(9to10heads) How this P(0to8heads)=1P(9to10heads)

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