When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A $1\mathrm{.}50-cm-$tall object is $51\mathrm{.}0$ cm to the left of a converging lens of focal length $40\mathrm{.}0$ cm $.$ A second converging lens, this one having a focal length of $60\mathrm{.}0$ cm $,$ is located $300$ cm to the right of the first lens along the same optic axis.

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Part A

Find the location and height of the image $($call it $I_1)$ formed by the lens with a focal length of $40\mathrm{.}0$ cm

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Part B

$I_1$ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.

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$s_2^{\text{'}},|y_2^{\text{'}}|=$

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