where B = C = and f ( u) = d) With the information found in (c), we find that [c e4/t's 74 dt = f(u)du = e) Hence, [c e4/+3 lim T-a Jb dt = lim f(u)du - Write +infty if the limit is too and -infty if the limit is -co. f) In conclusion, 2 e4/13 1 4 dt = Write Diverges if the integral is divergent.Question 4 Determine if the following integral converges or diverges. [2 e4/+3 +4 dt a 12 e4/13 e4/+3 t4 dt = lim T-ta Jb +4 -dt , where a = b = and C =. Number FORMATTING: To enter a one-sided limit value such as IT or 1-, write 1^+ or 1^- in Mobius. b) To compute the integral [ce4/13 +4 dt that you have found in (a), we need to use the change of variable u = c) With the change of variable that you have found in (b), we have [ce4/13 dt = /f (z) du- Question 6 A) Study the convergence of In (x) da, 8/5 and if the integral is convergent, give its value. A.1) The integral is Click for List A.2) If the integral converges, its exact value is Input 333 if the integral is divergent. B) Study the convergence of In (x) de, 8/5 and if the integral is convergent, give its value. B.1) The integral is Click for List B.2) If the integral converges, its exact value is Input 333 if the integral is divergent.Question 8 We wish to determine the convergence or divergence of the improper integral 6 + 2 COST dx 2+ 2x2 Choose the correct argument. 6 + 2 cos I The integral is divergent since > and 8 N | DO dx = 0o 2+ 2x2 6 + 2 cos I 6 The integral is divergent since 6 > and de = co. 2+ 2x2 8 8 The integral is convergent since 6 + 2 cos I for all a _ 1 and de =