Question: where do I go from here? Let f(x) = 2 sin x 4 sinx + 6 cos x Then f' (x) = (2 sin (x

where do I go from here?

Let f(x) = 2 sin x 4 sinx + 6 cos x Then f' (x) = (2 sin (x ) + 3 cos(x) ) 2 The equation of the tangent line to y = f(x) at a = can be written in the form y = mx + b where m = and Question Help: DVideo Submit

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