Where does the negative 3 come from? = = 3.1 [e d d dx [3e - cos(4x)
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Where does the negative 3 come from?
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= = 3.1 [e d d dx [3e - cos(4x) + x = 2] cos(4x) d dx s (4x)] + [x] + 1 [-2] d dx = d = 3e cos(4x). - cos(4x)] +1+0 - = 3e cos(4x) dx d (-2 [cos(4x)]) +1 dx d 3e-co (4x) (-sin(4x)) [4x] +1 d . dx = 3e cos(4x). 4. [x] sin(4x) +1 = = dx 12e cos(4x). 1 sin(4x) +1 - 12e cos(4x) sin(4x) +1 = = 3.1 [e d d dx [3e - cos(4x) + x = 2] cos(4x) d dx s (4x)] + [x] + 1 [-2] d dx = d = 3e cos(4x). - cos(4x)] +1+0 - = 3e cos(4x) dx d (-2 [cos(4x)]) +1 dx d 3e-co (4x) (-sin(4x)) [4x] +1 d . dx = 3e cos(4x). 4. [x] sin(4x) +1 = = dx 12e cos(4x). 1 sin(4x) +1 - 12e cos(4x) sin(4x) +1
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