where n$0=1$ and C $=538\mathrm{.}5.$ All log functions are base $2.$ And if you use log functions in your answers, they

should be base $2$ as well.

a$.$ t$($n$)=$ n $+($n $+1)++($n $+$ n$)$

b$.$ t$($n$)=$ log$5$ n $\backslash$times log$($n

$10)$

c$.$ t$($n$)=27$log$3$ n

d$.$ t$($n$)=1+5+52+53+...+5$n

e$.$ t$($n$)=2$n $+22$n $+2$n$+1$