Question: Which function defines (g - f)(x)?f(x) = 3?12x + 1 + 4g(x) = log(x ? 3) + 6A. (g-f)(x) = log x - 3?12x -

 Which function defines (g - f)(x)?f(x) = 3?12x + 1 +

4g(x) = log(x ? 3) + 6A. (g-f)(x) = log x -

Which function defines (g - f)(x)?f(x) = 3?12x + 1 + 4g(x) = log(x ? 3) + 6A. (g-f)(x) = log x - 3?12x - 12B. (g - f)(x) = log(x ? 3) - 3?12x+1 - 10C. (g - f)(x) = log(x - 3) - 3?12x+1 + 2D. (g - f)(x) = log(x - 3) - 3?12x+1 +10

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