Which statement best explains why $LiAl{H}_4$ is more reactive than $NaB{H}_4?$

a$.$ The $AI$ and $B$ atoms both have a negative formal charge in the structures of the two reagents. Because $B$ is more electronegative, it spreads more of the charge onto the $H$ atoms in $NaB{H}_4$ thus making them less nucleophilic.

b$.$ The $N{a}^{+}$ion forms a stronger ion$-$dipole intermolecular force with the carbonyl oxygen of the ketone or aldehyde thus making it less electrophilic.

c$.$ The $AI$ and $B$ atoms both have a negative formal charge in the structures of the two reagents. Because $Al$ is less electronegative, it spreads more of the charge onto the $H$ atoms in $LiAl{H}_4$ thus making them more nucleophilic.

d$.$ The $L{i}^{+}$ion forms a stronger ion$-$dipole intermolecular force with the carbonyl oxygen of the ketone or aldehyde thus making it more electrophilic.