Question: Which statement is true regarding this general (i.e. non-naive Bayes) form of Bayes' Rule?P(A|B) =P(b1,b2,b3,...,bm|A)P(A)/P(b1,b2,b3,...,bm) Answer choices Select an option The attributes b1 through bm
Which statement is true regarding this general (i.e. non-naive Bayes) form of Bayes' Rule?P(A|B) =P(b1,b2,b3,...,bm|A)P(A)/P(b1,b2,b3,...,bm) Answer choices Select an option The attributes b1 through bm are independent in the context of A. Since the denominator is a constant, P(A|B) is simply equal to the numerator. The denominator is not really needed. Because the attributes b1 through bm are independent of A, the first term in the numerator equals the value of the denominator, and therefore P(A|B) = P(A). All of the other answers are false
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