Question: } while ( minchange 0 ) ; Notice that when min _ i and min _ j are found, we apply the associated two opt

} while (minchange 0);
Notice that when min_i and min_j are found, we apply the associated two opt move in the code however this part is not represented in the code (instead it is mentioned as //apply mini/minj move in the code). You may assume the associated two-opt move is also similarly adopted in the questions that are given below.
A) Suppose we want to terminate the two-opt algorithm in 10000 iterations. Update the code accordingly.
B) Suppose we want to terminate the two-opt algorithm when the objective function cannot be improved more than 5%. Update the code accordingly
C) What is the difference of the above-given pseudo-code from (A) and (B)?
} while ( minchange < 0 ) ; Notice that when min

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