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Write code that uses the ternary operator (Section 6.6 in case you need to review) to answer the problem. User inputs a year o If the year is a leap year then output "?? is a Leap year" where ?? Is the year entered o If the year is NOT a leap year then output "?? is not a Leap year" where ?? Is the year entered Calculate a Leap Year: Any year that is evenly divisible by 4 is a leap year: for example, 1988, 1992, and 1996 are leap years. However, there is still a small error that must be accounted for. To eliminate this error, any year that is evenly divisible by 100 (for example, 1900) is a leap year only if it is also evenly divisible by 400. Sample output Enter year: 2000 2000 is Leap year. Enter year: 2017 2017 is not a Leap year. Enter year: 1900 1900 is not a Leap year. Enter year: 2016 2016 is Leap year