Why does the following code print this $(<\_\_$main$\_\_.$List$135$ object at $0$x$000001$D$240$A$3$CD$30>,1)?$ I want the function firstN to return the first n elements of a list$135$ object $($xs$)$ as a new list$135$ object and output $[1,2]$ in this example

class List$135$:

# create new list node. Defaults to a node representing the empty list

def $\_\_$init$\_\_($self$,$ initdata$=$None, initnext$=$None$)$:

self.$\_$data $=$ initdata

self.$\_$next $=$ initnext

# is the list beginning with self the end of the list?

def empty$($self$)$:

return self.$\_$next $==$ None

# return the first element of the list that starts with self

def first$($self$)$:

return self.$\_$data

# return the list that begins after the list that starts with self

def rest$($self$)$:

return self.$\_$next

# return a list beginning with data, followed by list beginning with self

def add$($self$,$ data$)$:

return List$135($data$,$ self$)$

# tail$-$recursively accumulates $","+$ str$($cur$.\_$data$)$ for each remaining item

def $\_$str$($self$,$ cur, acc$)$:

if cur.$\_$next $==$ None:

return acc

else:

nextacc $=$ acc $+","+$ str$($cur$.\_$data$)$

nextcur $=$ cur.$\_$next

return self.$\_$str$($nextcur$,$ nextacc$)$

def $\_\_$str$\_\_($self$)$:

if self.$\_$next $==$ None:

return $"[]"$

else:

acc $=$ str$($self$.\_$data$)$ # init accumulator with first item

cur $=$ self.$\_$next # continue accumulation with next

return $"["+$ self.$\_$str$($cur$,$ acc$)+"]"$

def firstN$($xs$,$ n$)$:

if n $==0$:

return temp

else:

temp $=$ List$135()$

temp.add$($xs$.$first$())$

return $($xs$.$rest$(),$ n$-1)$

if $\_\_$name$\_\_==\text{'}\_\_$main$\_\_\text{'}$:

xs $=$ List$135().$add$(3).$add$(2).$add$(1)$

zs $=$ firstN$($xs$,2)$

print$($str$($zs$))$