Question: why does the graph look like this? It supposes to be a proportional function. Screen Shot 2020-02-11 at 00.14.04 Search Edit View Insert Figure 1

why does the graph look like this? It supposes to be a proportional function.why does the graph look like this? It supposes to be a

Screen Shot 2020-02-11 at 00.14.04 Search Edit View Insert Figure 1 Tools Desktop Window Help Run Section Advance Run and Insert 3 fx > GOTO - Comment % Breakpoints Run Run and Find - Indent NAVIGATE EDIT BREAKPOINTS weisenji Documents MATLAB Editor-/Users/weisenji/Documents MATLAB/untitled 3.m untitled2.m untitled3. m x untitled 6.m x + xlabel('T'); ylabel('inik)'); title'function of T with Inikl '); lambda = .96; H_ad = 0.1; T = 300; deltag = .1; h = 1.854571628*19*(-34); k_b = 1.3806504*19^(-23); x = linspace', 1, 180); FC = (1./sart(4.*pi. lambda.sk_b.(1./X))).*exp(-(deltag + lambdal.^2)./(4. lanbda.*k_b.*(1./X))); y = FC.*((2.* pi)./h). * H_ad).^2; plot(x,y) xlin[,.0000016900000000001] 13 - O 0.1 0.2 0.3 0.7 0.8 0. 9 1 amodiodou 0.4 0.5 0.6 a IMG 0012.jpg @ Search I @ @ @ @ Q Search kg = g (Med?!FC, (S2) FC = expl-@* + 2)2/(41K67)

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!