Question: Why does the quantity 1 n i = 1 n f ( x i ) perform poorly for estimating f ( x ) d x

Why does the quantity 1ni=1nf(xi) perform poorly for estimating f(x)dx? The quantity is an accurate estimate for the integral. 1ni=1nf(xi)E(f(x))f(x)dx Since we do not know the distribution of f(xi), we cannot find any distributional results about the sample average and thus the CLT does not apply and 1ni=1?f(xi). We do not know if f(xi) are independent, so we cannot say anything about the asymptotic behavior of the sample average.
 Why does the quantity 1ni=1nf(xi) perform poorly for estimating f(x)dx? The

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