Why does this version of the swap function fail to work? Is there a fix? $($Choose $2)$

void swap$($int & lhs$,$ int& rhs$)$

$\{$

lhs $=$ rhs;

rhs $=$ lhs;

$\}$

Group of answer choices

It fails OK$,$ and we can fix it we can just reverse the order of the lines.

a$)$ To fix this, we must save the lhs value in a local variable before making the first assignment indicated, then instead of the second line, assign the rhs the value of the local variable:

int local $=$ lhs;

lhs $=$ rhs;

rhs $=$ local;

It fails because the first line destroys the old value of lhs without saving it$.$ Then both variables have the old value of rhs in them.

It fails because the programmer forgot to make the parameters call$-$by$-$reference.